Day 1: Who likes it?

Day 1: Who likes it?

Code challenge series day one.

In this weekly series, I will be taking out coding problems from CodeWars and sharing a step-by-step tutorial on how exactly I was able to solve it on my first trial. It is important to keep in mind that my solution may not be in-line with modern practices and techniques, however it is going to be correct. Which is all that really matters lol.

This is an initiative I thought up recently and I hope it helps beginners learn how to program with JavaScript.

So, let's dive in!

Who likes it?

Today's challenge is going to be quite interesting. If you use social media platforms like Facebook, you should by now know of the 'likes' feature where images and posts get liked by users and readers.

In this challenge, we are going to be creating a function which returns different customized messages depending on the number of likers a post gets.

Here are the rules:

likes[]   // "No one likes this"
likes["Jack"]     // "Jack likes this"
likes["Jack", "Jacob"]      // "Jack and Jacob likes this"
likes["Jack", "Jacob", "Jill"]      // "Jack, Jacob and Jill likes this"
likes["Jack", "Jacob", "Jill", "John"]      // "Jack, Jacob and 2 others liked this"

As you can see, the likes() function takes in an array of users who likes a post and returns a different message depending on if one, two, three or four and more users liked the post.

I pulled this test out of a 6 kyu challenge on CodeWars.

Without further ado, let's dig in!

SOLUTION

The first step I always take when solving a coding problem is to break them down into logical steps and representing each of these steps in pseudocode.

STEP 1: CHECKING IF ANYONE LIKED IT

Define the likes function. This function will take in Array of names (strings) First step to take inside the function is to define an if statement: Check to see if the length of the array is falsy (that is, the array is empty and no one liked the post).

If it is empty, return a string with the meaage which says "No one likes this post"

function likes ( ...names ) {
  if( !names.length) {
     return "No one likes this";
 }

// Continuation

STEP 2: LOOPING OVER THE ARRAY AND STORING NUMBER OF LIKERS

If we got to this point, it means that there is atleast one name present in the Array. Create a count variable and set its value to zero. After you are done with that, loop through the list of name. For every iteration you make, increment the value of count by one.


let count = 0;
names.forEach(name => count++);

STEP 3: CHECKING TO SEE HOW MANY LIKED

Step 2 was about looping through the array and increasing the count by one for every likers encountered.

Now, we are going to implement a chain of conditional statements which is geared towards returning a new message for every number of likers.

First statement checks if the count variable is one, which means that one person liked the post. If true, we will get the name of the sole liker and return the following message: insert_liker_name likes this post

Second statement checks if the count variable is two, which means that two people liked the post. If true, we will get the name of the two likers and return the following message: liker_1 and liker_2 likes this post

Third statement checks if the count variable is three, which means that three people liked the post. If true, we will get the name of the three likers and return the following message: liker_1, liker_2 and liker_3 likes this post

The fourth and final statement checks if the count variable is four or above, which means that at least four people liked the post. If true, we will first subtract two (i.e the people who will be displayed) from the number of likers, that is count. Then we will get the first two names from the list of likers and return the following message: liker_1, liker_2 and remaining_numbers likes this post

if(count == 1) {
    const firstName = names[0];
    return `${firstName} likes this post`
  } else if (count == 2) {
    const firstName = names[0]
    const secondName = names[1]
    return `${firstName} and ${secondName} likes this post`
  }
  else if (count == 3) {
    const firstName = names[0]
    const secondName = names[1]
    const thirdName = names[2]
    return `${firstName}, ${secondName} and ${thirdName} likes this post`
  } else {
    const remainder = count - 2;
    const firstName = names[0]
    const secondName = names[1]
    return `${firstName}, ${secondName} and ${remainder} others likes this post`
  }

}

Now, lets see the full program:

function likes(...names) {
  if(!names.length) {
    return "No one likes this";
  }

  let count = 0;
  names.forEach(name => count++);

  if(count == 1) {
    const firstName = names[0];
    return `${firstName} likes this post`
  } else if (count == 2) {
    const firstName = names[0]
    const secondName = names[1]
    return `${firstName} and ${secondName} likes this post`
  }
  else if (count == 3) {
    const firstName = names[0]
    const secondName = names[1]
    const thirdName = names[2]
    return `${firstName}, ${secondName} and ${thirdName} likes this post`
  } else {
    const remainder = count - 2;
    const firstName = names[0]
    const secondName = names[1]
    return `${firstName}, ${secondName} and ${remainder} others likes this post`
  }

}

const likers = ["Jack", "Jill"]

console.log(likes(...likers));

RESULT

JSFiddle-Code-Playground.png

JSFiddle-Code-Playground (1).png

This simple challenge was really fun for me on the first trial and I hope it was the same for you. You can copy the code and test it yourself on JS Fiddle.

If you have a better way of solving this problem, please put it down in the comments. I'd love to check it out. If you have any suggestions, I'd love to hear it!

I will be doing this every Mondays, Wednesdays and Fridays. Follow/Subscribe to this blog to be updated. I will be tackling a new challenge in public on Friday.

Until then, friends!

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P/S: If you are learning JavaScript, I recently created an eBook which teaches 50 topics in hand-written notes. Check it out here

 
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